Telltale Games

Avistew · 05/31/2010, 10:25 pm

You mean a square and two diagonals? If that's the case, explain to me how you figure that they're equilateral

Harald B · 05/31/2010, 10:28 pm

Doh. Er, nevermind.

flesk · 05/31/2010, 10:56 pm

Solution to A:

|><|
|><|

Two intertwined equilateral triangles, where the "top" of one triangle touches the "bottom" of the other, and vice versa.

On B:

Wouldn't a Star of David make six equilateral triangles like you originally posted?

Avistew · 05/31/2010, 11:04 pm

Quote:

Originally Posted by bamse

Solution to A:

|><|
|><|

Two intertwined equilateral triangles, where the "top" of one triangle touches the "bottom" of the other, and vice versa.

On B:

Wouldn't a Star of David make six equilateral triangles like you originally posted?

No, six small ones and two big ones, so eight altogether. I'm not sure if your solution is indeed equilateral triangles but I'm guessing if they are there are six of them. Either way, that's not the solution I was looking for, but that's definitely an interesting suggestion.

flesk · 05/31/2010, 11:44 pm

Quote:

Originally Posted by Avistew

No, six small ones and two big ones, so eight altogether. I'm not sure if your solution is indeed equilateral triangles but I'm guessing if they are there are six of them. Either way, that's not the solution I was looking for, but that's definitely an interesting suggestion.

Ah, I didn't even think of the bigger ones. Yeah, they are equilateral, but like you said, there are six of them when you count the two big ones.

Avistew · 05/31/2010, 11:49 pm

Okay, everyone, bamse didn't find the answer to A, but the answer to C (6 equilateral triangles with 6 matches), which deserves kudos too.

flesk · 06/01/2010, 12:11 am

Create the rhombus
A___B
/ /
/___/
D C

where ADC = ABC = 60 degrees. Join corners A and C. Join lines AB and CD with a match parallel to AD and BC. Call the point where the last two matches meet X, the point where the last match meets AB Y and the point where the last match meets CD Z.
We have equilateral triangles ACD, ACB, AXY and CXZ.

Avistew · 06/01/2010, 12:36 am

That looks super complicated and I have no clue if they're equilateral or not, but that's not the answer I'm looking for.

Just like the answer to B, the answer to A can be given with words, without any drawing or anything involved. If that helps. I'll even accept both the tabletop RPG term and the geometry one.

flesk · 06/01/2010, 01:02 am

Here's an attempt at some more descriptive ASCII art of my solution:

...____
../\/.../
././\../
/_/_\/

It consists of two large equilateral triangles, where one is upside down, and they share one match. The sixth match can be anywhere, touching the top and bottom line, but must be parallel to the left and right side.

Avistew · 06/01/2010, 01:06 am

Ah, I see. Looks good to me. Congrats then! Wasn't the solution I was looking for (mine has 4 equilateral triangles that are the same size, and doesn't require any calculating) but if it works you get points. Want to try and figure out the one I had in mind or should I give the solution?

Here is a hint: Every side of every triangle is one match. That's why you don't need to calculate anything, since all matches are the same size.

doodinthemood · 06/01/2010, 01:09 am

This is what bamse has done:

I followed his instructions XD It does work. Just not especially nice, and the triangles are different sizes, and two matches cross.

Javi-Wan Kenobi · 06/01/2010, 01:20 am

The answer to A (4 equilateral triangles using 6 matches) is a tetrahedron (triangular pyramid with 4 equal sides). The trick is thinking beyond the 2D

Avistew · 06/01/2010, 01:20 am

Well, bamse gets credit for figuring out a new solution.

Javi-Wan Kenobi · 06/01/2010, 01:26 am

I've got one:
How do you get seven as the result of dividing twelve by two?

Avistew · 06/01/2010, 01:34 am

Oh, I know! But I figured it out so fast, I think I knew it already, so I won't say.

Neelo · 06/01/2010, 06:32 am

Quote:

Originally Posted by Javi-Wan Kenobi

I've got one:
How do you get seven as the result of dividing twelve by two?

When you suck at math and don't have a calculator?

Didero · 06/01/2010, 06:51 am

Just keep dividing by 2 until you reach 0.75?

The Highway · 06/01/2010, 06:55 am

cheat?

Javi-Wan Kenobi · 06/01/2010, 06:56 am

You only divide once, and it's an exact (and -somehow- correct) division

Avistew · 06/01/2010, 07:03 am

Well, since I don't want to hold the whole thread up, the answers I would have accepted are d4, tetrahedron and, while inaccurate, pyramid (because I would have assumed you just didn't know the right word).

05/31/2010, 10:28 pm	#222
Harald B Egregious Philosopher Join Date: Jan 2007 Posts: 1,448	Doh. Er, nevermind. __________________ although we do still have a time machine, so I wouldn't completely rule out the possibility. Forgot what T.H.E.M. stands for? Need the lyrics to the War Song? Visit the Sam & Max wiki!

06/01/2010, 01:09 am	#231
doodinthemood Your 4th favourite member Join Date: Jul 2009 Location: Birmingham England Kudos: 867 Posts: 975	This is what bamse has done: I followed his instructions XD It does work. Just not especially nice, and the triangles are different sizes, and two matches cross. __________________ Hi Logan. I know you're reading this.

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05/31/2010, 10:25 pm	#221
Avistew I<3>1 Join Date: Jun 2009 Location: France Posts: 5,051	You mean a square and two diagonals? If that's the case, explain to me how you figure that they're equilateral

05/31/2010, 10:56 pm	#223
flesk Senior Member Join Date: Sep 2008 Location: Norway Posts: 679	Solution to A: \|><\| \|><\| Two intertwined equilateral triangles, where the "top" of one triangle touches the "bottom" of the other, and vice versa. On B: Wouldn't a Star of David make six equilateral triangles like you originally posted?

05/31/2010, 11:49 pm	#226
Avistew I<3>1 Join Date: Jun 2009 Location: France Posts: 5,051	Okay, everyone, bamse didn't find the answer to A, but the answer to C (6 equilateral triangles with 6 matches), which deserves kudos too.

06/01/2010, 12:11 am	#227
flesk Senior Member Join Date: Sep 2008 Location: Norway Posts: 679	Create the rhombus A___B / / /___/ D C where ADC = ABC = 60 degrees. Join corners A and C. Join lines AB and CD with a match parallel to AD and BC. Call the point where the last two matches meet X, the point where the last match meets AB Y and the point where the last match meets CD Z. We have equilateral triangles ACD, ACB, AXY and CXZ.

06/01/2010, 12:36 am	#228
Avistew I<3>1 Join Date: Jun 2009 Location: France Posts: 5,051	That looks super complicated and I have no clue if they're equilateral or not, but that's not the answer I'm looking for. Just like the answer to B, the answer to A can be given with words, without any drawing or anything involved. If that helps. I'll even accept both the tabletop RPG term and the geometry one.

06/01/2010, 01:02 am	#229
flesk Senior Member Join Date: Sep 2008 Location: Norway Posts: 679	Here's an attempt at some more descriptive ASCII art of my solution: ...____ ../\/.../ ././\../ /_/_\/ It consists of two large equilateral triangles, where one is upside down, and they share one match. The sixth match can be anywhere, touching the top and bottom line, but must be parallel to the left and right side.

06/01/2010, 01:06 am	#230
Avistew I<3>1 Join Date: Jun 2009 Location: France Posts: 5,051	Ah, I see. Looks good to me. Congrats then! Wasn't the solution I was looking for (mine has 4 equilateral triangles that are the same size, and doesn't require any calculating) but if it works you get points. Want to try and figure out the one I had in mind or should I give the solution? Here is a hint: Every side of every triangle is one match. That's why you don't need to calculate anything, since all matches are the same size.

06/01/2010, 01:20 am	#232
Javi-Wan Kenobi Adventure Gaming Jedi Join Date: Jul 2009 Location: Estella, Navarra, Spain Posts: 1,060	The answer to A (4 equilateral triangles using 6 matches) is a tetrahedron (triangular pyramid with 4 equal sides). The trick is thinking beyond the 2D

06/01/2010, 01:20 am	#233
Avistew I<3>1 Join Date: Jun 2009 Location: France Posts: 5,051	Well, bamse gets credit for figuring out a new solution.

06/01/2010, 01:26 am	#234
Javi-Wan Kenobi Adventure Gaming Jedi Join Date: Jul 2009 Location: Estella, Navarra, Spain Posts: 1,060	I've got one: How do you get seven as the result of dividing twelve by two?

06/01/2010, 01:34 am	#235
Avistew I<3>1 Join Date: Jun 2009 Location: France Posts: 5,051	Oh, I know! But I figured it out so fast, I think I knew it already, so I won't say.

06/01/2010, 06:51 am	#237
Didero Senior Member Join Date: Jun 2009 Location: The Netherlands Posts: 481	Just keep dividing by 2 until you reach 0.75?

06/01/2010, 06:55 am	#238
The Highway Resident Voodoo Master Join Date: Mar 2009 Location: Pathetic Perth Telltale Games Level: 3,652 Posts: 3,623	cheat?

06/01/2010, 06:56 am	#239
Javi-Wan Kenobi Adventure Gaming Jedi Join Date: Jul 2009 Location: Estella, Navarra, Spain Posts: 1,060	You only divide once, and it's an exact (and -somehow- correct) division

06/01/2010, 07:03 am	#240
Avistew I<3>1 Join Date: Jun 2009 Location: France Posts: 5,051	Well, since I don't want to hold the whole thread up, the answers I would have accepted are d4, tetrahedron and, while inaccurate, pyramid (because I would have assumed you just didn't know the right word).